4y^2-60y-148=0

Solution for 4y^2-60y-148=0 equation:

4y^2-60y-148=0

a = 4; b = -60; c = -148;
Δ = b2-4ac
Δ = -602-4·4·(-148)
Δ = 5968
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5968}=\sqrt{16*373}=\sqrt{16}*\sqrt{373}=4\sqrt{373}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-4\sqrt{373}}{2*4}=\frac{60-4\sqrt{373}}{8}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+4\sqrt{373}}{2*4}=\frac{60+4\sqrt{373}}{8}
$